Wednesday 25 November 2015

Light Up the World!

Image result for lightbulb earth
How many AA batteries would it take to power all the light in all the houses of the whole world?

I'm not interested in a correct answer, as there isn't one.

I'm interested in how you try to solve the problem.

Explain all of your thinking.

(This is a chance to show off some logical thinking)

14 comments:

  1. I would this out by finding the batteries in a big continent and a small/medium continent, add it up and times it by 3.5 because there are 7 continents on Earth and we are dividing them by 2.

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  2. There are about 248,752 cities are in the world and there are approximately 7375 people in a city. They need at least 1 light in a bathroom, kitchen, bedroom, living room. Then you have to times 248,752 with 7375 and it is 1834546000 and we need 6 batteries to light it brightly so you have to times 1834546000 with 6 which is 11007276000. Consequently we need 11007276000 batteries to light up all the bulbs in the world.


    Sri

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  3. This comment has been removed by a blog administrator.

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  4. There are about 7 million cities in the world ( I estimated that there are approximately one tenth of cities of the population of the whole world). In each building there are abount 36 lights in each one. 3 batteries per light. 36x3= 108. If there are around 7 millio cities in the world, then 108x7,000,000= 756,000,000.

    Therefore, my answer is 756,000,000

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  5. Approximately, there are 7 billion people in the world.
    However, according to official figures on scientificamerican.com, 1.5 billion people are unable to access electricity.
    Taking away the 1.5 billion, there are 5.5 billion people who use electricity.
    There would probably 40% living in an average family size of 5 ; the other 40% in a couple ; the remainder 20% alone.
    40%=2.2 billion
    20%=1.1 billion
    So to find how many houses with families there are, you have to do 2.2 billion/5=0.44 billion
    Houses with couples = 1.1 billion
    Houses with 1 person = 1.1 billion
    Altogether, there are 2.64 billion houses. Assuming every house has a bathroom, living room,hallway, dining room, landing, kitchen and two bedrooms, there are 8 bulbs in a house. Also assuming, 3 cells can power 1bulb. 3 cells x 8 bulbs is 24.
    24x2.64 billion=63.36
    So this means it would take 63.36 billion AA cells to power all the houses in the world.

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    Replies
    1. Wow!
      What wonderful logic. I have no idea what the true answer is but I wouldn't be shocked to find out that your were close.

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    2. Wow...
      That is incredible logic. I agree with Mr lovelock, whatever the right answer is I am sure that you would be somewhere close to the answer.

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    3. Thank you Mr Lovelock! I didn't take much, just a moment's thought. Or twenty.

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    4. nice effort SO MUCH LOGIC !
      very COMPLECATED!
      SO PRESICE !
      NICE ESTIMATE!

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  6. Well, Europe,North America,South America and parts of Asia are the main continents with electricity.

    As Quynh-Chau said the global population is around 7 billion.There are around 7-10 million cities in the

    world but about one-third of them don't have electricity.
    There are 2.65 billion homes in the world and each one has 36 light bulbs in them. (That was an overall) average. Making the assumption that three AA cells are needed to power one bulb, the sum is

    2,640,000,000x36x3 which is 285,185,000,000. So, about 285 billion.

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  7. 197 countries
    2,5 million cities
    197 x 2,5 million = [or something like that]
    =20 billion ????????

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  8. 1850000000 AA BATTRIES

    WORKED OUT

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  9. As the world has 197 countries and a population of 7.2 billion and about 125 million dwellings in the world.
    It would take 11 AA batteries to light a 120 volt bulb.

    197*11 or 125*11

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    Replies
    1. it is ment to be 120 WATT bulb

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